constellations and equatorial grid begin date: 9/9/2025 12:01:00 am due date: 9/12/2025 11:59:00 pm end problem 21: (3% of assignment value) astronomers subdivide degrees down into arcminutes and arcseconds. ... part (a) suppose a constellation has an angular width of 25°. how many arcminutes does this equate to? 25° = 1500. arcmin correct! part (b) how many arcseconds are there in that angle? 25 = arcsec

Question

constellations and equatorial grid  begin date: 9/9/2025 12:01:00 am due date: 9/12/2025 11:59:00 pm end problem 21: (3% of assignment value) astronomers subdivide degrees down into arcminutes and arcseconds. ... part (a) suppose a constellation has an angular width of 25°. how many arcminutes does this equate to? 25° = 1500. arcmin correct! part (b) how many arcseconds are there in that angle? 25 =   arcsec

Accepted Answer

# Explanation:
## Step1: Recall the conversion factor between degrees, arcminutes, and arcseconds. We know that $1^\circ = 60$ arcmin and $1$ arcmin $= 60$ arcsec, so $1^\circ = 60\times60 = 3600$ arcsec.
## Step2: To find the number of arcseconds in $25^\circ$, we multiply the number of degrees by the number of arcseconds in one degree. So we calculate $25\times3600$.
$25\times3600 = 90000$

# Answer:
90000

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Question

Explanation:

Step1: Recall the conversion factor between degrees, arcminutes, and arcseconds. We know that \(1^\circ = 60\) arcmin and \(1\) arcmin \(= 60\) arcsec, so \(1^\circ = 60\times60 = 3600\) arcsec.

Step2: To find the number of arcseconds in \(25^\circ\), we multiply the number of degrees by the number of arcseconds in one degree. So we calculate \(25\times3600\).

Answer: