Question

1. construct the perpendicular bisector of

1.
2.
3.
ii. bisect side $overline{yz}$ of $\triangle xyz$.
4.
5.

Explanation:

Step1: For constructing perpendicular - bisector of line segment

For a line segment $\overline{AB}$:

1. Set the compass width to more than half the length of $\overline{AB}$.
2. With center $A$, draw two arcs, one above and one below $\overline{AB}$.
3. Without changing the compass width, with center $B$, draw two arcs, one above and one below $\overline{AB}$ to intersect the previous arcs. Let the intersection points of the arcs be $C$ and $D$.
4. Draw the line $\overline{CD}$. $\overline{CD}$ is the perpendicular - bisector of $\overline{AB}$.

For line segment $\overline{EF}$, follow the same steps as above.

Step2: For bisecting side $\overline{YZ}$ of $\triangle XYZ$

1. Set the compass width to more than half the length of $\overline{YZ}$.
2. With center $Y$, draw two arcs, one on each side of $\overline{YZ}$.
3. Without changing the compass width, with center $Z$, draw two arcs to intersect the previous arcs. Let the intersection points of these arcs be two new points.
4. Draw the line passing through these two intersection points. This line bisects side $\overline{YZ}$ of $\triangle XYZ$.

Answer:

Follow the above - described geometric construction steps for each of the line segments and the side of the triangle to complete the tasks.