QUESTION IMAGE
Question
convert the following to scientific notation.
- 0.005 =
- 5,050 =
- 0.0008 =
- 1,000 =
- 1,000,000 =
- 0.25 =
- 0.025 =
- 0.0025 =
- 500 =
- 5,000 =
Step1: Recall scientific - notation form
Scientific notation is $a\times10^{n}$, where $1\leqslant|a|\lt10$ and $n$ is an integer.
Step2: Convert 0.005
Move the decimal point 3 places to the right to get $a = 5$. Since we moved the decimal point 3 places to the right, $n=-3$. So, $0.005 = 5\times10^{-3}$.
Step3: Convert 5050
Move the decimal point 3 places to the left to get $a = 5.05$. Since we moved the decimal point 3 places to the left, $n = 3$. So, $5050=5.05\times10^{3}$.
Step4: Convert 0.0008
Move the decimal point 4 places to the right to get $a = 8$. Since we moved the decimal point 4 places to the right, $n=-4$. So, $0.0008 = 8\times10^{-4}$.
Step5: Convert 1000
Move the decimal point 3 places to the left to get $a = 1$. Since we moved the decimal point 3 places to the left, $n = 3$. So, $1000=1\times10^{3}$.
Step6: Convert 1000000
Move the decimal point 6 places to the left to get $a = 1$. Since we moved the decimal point 6 places to the left, $n = 6$. So, $1000000=1\times10^{6}$.
Step7: Convert 0.25
Move the decimal point 1 place to the right to get $a = 2.5$. Since we moved the decimal point 1 place to the right, $n=-1$. So, $0.25 = 2.5\times10^{-1}$.
Step8: Convert 0.025
Move the decimal point 2 places to the right to get $a = 2.5$. Since we moved the decimal point 2 places to the right, $n=-2$. So, $0.025 = 2.5\times10^{-2}$.
Step9: Convert 0.0025
Move the decimal point 3 places to the right to get $a = 2.5$. Since we moved the decimal point 3 places to the right, $n=-3$. So, $0.0025 = 2.5\times10^{-3}$.
Step10: Convert 500
Move the decimal point 2 places to the left to get $a = 5$. Since we moved the decimal point 2 places to the left, $n = 2$. So, $500=5\times10^{2}$.
Step11: Convert 5000
Move the decimal point 3 places to the left to get $a = 5$. Since we moved the decimal point 3 places to the left, $n = 3$. So, $5000=5\times10^{3}$.
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