Question

1. the coordinates of quadrilateral efgh and its image are: quadrilateral efgh e(-5, 5) f(-3, 4) g(-2, 1) h(-4, 2) quadrilateral efgh e(-5, 2) f(-3, 1) g(-2, -2) h(-4, -1) describe the transformation that made image efgh

Explanation:

Step1: Analyze x - coordinates

The x - coordinates of the original points \(E(-5,5)\), \(F(-3,4)\), \(G(-2,1)\), \(H(-4,2)\) and the image points \(E'(-5,2)\), \(F'(-3,1)\), \(G'(-2, - 2)\), \(H'(-4,-1)\) are the same. That is, for point \(E\), \(x=-5\) in both \(E\) and \(E'\), for \(F\), \(x = - 3\) in both \(F\) and \(F'\), for \(G\), \(x=-2\) in both \(G\) and \(G'\), and for \(H\), \(x=-4\) in both \(H\) and \(H'\).

Step2: Analyze y - coordinates

For point \(E\), \(y = 5\) in \(E\) and \(y = 2\) in \(E'\), \(5-2 = 3\). For point \(F\), \(y = 4\) in \(F\) and \(y = 1\) in \(F'\), \(4 - 1=3\). For point \(G\), \(y = 1\) in \(G\) and \(y=-2\) in \(G'\), \(1-(-2)=3\). For point \(H\), \(y = 2\) in \(H\) and \(y=-1\) in \(H'\), \(2-(-1)=3\). The y - coordinate of each point of the original quadrilateral is decreased by 3 to get the y - coordinate of the corresponding point of the image.

Answer:

A translation 3 units down.