Question

current learning objective: writing the equations of lines parallel or perpendicular to a given line
question 11
score: 0 of 1 point
find the equation of the line that passes through the point (-3, -6) and is parallel to the line y = 4x + 4.
a y=-3x + 6
b y = 4x+4
c y = 4x+6
d y=-3x + 4
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Explanation:

Step1: Determine the slope

Parallel lines have the same slope. The given line is $y = 4x+4$, which is in slope - intercept form $y=mx + b$ where $m$ is the slope. So the slope of the line we want to find is $m = 4$.

Step2: Use the point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $(x_1,y_1)=(-3,-6)$ and $m = 4$. Substitute these values: $y-(-6)=4(x - (-3))$.

Step3: Simplify the equation

$y + 6=4(x + 3)$. Expand the right - hand side: $y+6 = 4x+12$. Then subtract 6 from both sides to get the slope - intercept form: $y=4x + 6$.

Answer:

C. $y = 4x+6$