Question

d105a
kumon
division by 2 - digit numbers 3
◆ divide.
(1)
\\(\

$$\begin{array}{r}\ 83\\enclose{longdiv}{180}\ \\end{array}$$

\\)
(5)
\\(\

$$\begin{array}{r}\ 84\\enclose{longdiv}{180}\ \\end{array}$$

\\)
(2)
\\(\

$$\begin{array}{r}\ 83\\enclose{longdiv}{252}\ \\end{array}$$

\\)
(6)
\\(\

$$\begin{array}{r}\ 84\\enclose{longdiv}{252}\ \\end{array}$$

\\)
(3)
\\(\

$$\begin{array}{r}\ 83\\enclose{longdiv}{415}\ \\end{array}$$

\\)
(7)
\\(\

$$\begin{array}{r}\ 84\\enclose{longdiv}{415}\ \\end{array}$$

\\)
(4)
\\(\

$$\begin{array}{r}\ 83\\enclose{longdiv}{567}\ \\end{array}$$

\\)
(8)
\\(\

$$\begin{array}{r}\ 84\\enclose{longdiv}{567}\ \\end{array}$$

\\)

Explanation:

Step1: Divide 180 by 83

Find how many times 83 fits into 180: $83 \times 2 = 166$, remainder $180 - 166 = 14$.
Result: $2$ remainder $14$ or $\frac{180}{83}=2+\frac{14}{83}$

Step2: Divide 252 by 83

$83 \times 3 = 249$, remainder $252 - 249 = 3$.
Result: $3$ remainder $3$ or $\frac{252}{83}=3+\frac{3}{83}$

Step3: Divide 415 by 83

$83 \times 5 = 415$, remainder $0$.
Result: $5$

Step4: Divide 567 by 83

$83 \times 6 = 498$, remainder $567 - 498 = 69$.
Result: $6$ remainder $69$ or $\frac{567}{83}=6+\frac{69}{83}$

Step5: Divide 180 by 84

$84 \times 2 = 168$, remainder $180 - 168 = 12$.
Result: $2$ remainder $12$ or $\frac{180}{84}=2+\frac{12}{84}=2+\frac{1}{7}$

Step6: Divide 252 by 84

$84 \times 3 = 252$, remainder $0$.
Result: $3$

Step7: Divide 415 by 84

$84 \times 4 = 336$, remainder $415 - 336 = 79$.
Result: $4$ remainder $79$ or $\frac{415}{84}=4+\frac{79}{84}$

Step8: Divide 567 by 84

$84 \times 6 = 504$, remainder $567 - 504 = 63$.
Result: $6$ remainder $63$ or $\frac{567}{84}=6+\frac{63}{84}=6+\frac{3}{4}$

Answer:

1. $2$ remainder $14$
2. $3$ remainder $3$
3. $5$
4. $6$ remainder $69$
5. $2$ remainder $12$
6. $3$
7. $4$ remainder $79$
8. $6$ remainder $63$