Question

day 5 - 8th grade science staar reviewnamedateforce, motion, and energy - teks 8.6c (r), 7.7a (s), 6.8a (s), 6.9c (s)5. the data chart below indicates how carts of different mass accelerate when a constant force is applied. using the data, determine the amount of force used in newtons.| mass (kg) | 1.0 | 2.0 | 4.0 | 8.0 || ---- | ---- | ---- | ---- | ---- || acceleration ($m/s^{2}$) | 4.0 | 2.0 | 1.0 | 0.5 |a 1 nb 2 nc 4 nd 8 n6. josh hamilton crushes a home run over the center field wall. the ball is struck with a force of 20 n. how much force does the ball apply to the bat?a 5 nb 10 nc 20 nd 40 n7. suppose you launch two different model rockets using two different engines. each engine produces a different amount of force, and you record the following acceleration data for each rocket.| engine/rocket number | force of engine | acceleration || ---- | ---- | ---- || engine/rocket #1 | 2 n | $4 m/s^{2}$ || engine/rocket #2 | 1 n | $2 m/s^{2}$ |what conclusion can you reach about the mass of the two rockets?a the mass of the two rockets are the same.b the mass of the first rocket is double the mass of the second rocket.c the mass of the second rocket is double the mass of the first rocket.d there is not enough information to compare the mass of the two rockets.8. a tennis ball being dropped, then bouncing upward after hitting the ground is an example of:a the law of inertiab the law of force and accelerationc the law of action-reactiond the law of reflection© hedgehog learning. copying allowed for purchasing school only.

Explanation:

Step1: Solve Q5 using $F=ma$

For each cart:

• Cart 1: $F = 1.0\ \text{kg} \times 4.0\ \text{m/s}^2 = 4\ \text{N}$
• Cart 2: $F = 2.0\ \text{kg} \times 2.0\ \text{m/s}^2 = 4\ \text{N}$
• Cart 3: $F = 4.0\ \text{kg} \times 1.0\ \text{m/s}^2 = 4\ \text{N}$
• Cart 4: $F = 8.0\ \text{kg} \times 0.5\ \text{m/s}^2 = 4\ \text{N}$

Step2: Solve Q6 with action-reaction

Newton's 3rd law states reaction force equals applied force: $F_{\text{ball on bat}} = 20\ \text{N}$

Step3: Solve Q7 using $m=\frac{F}{a}$

• Rocket 1: $m_1 = \frac{2\ \text{N}}{4\ \text{m/s}^2} = 0.5\ \text{kg}$
• Rocket 2: $m_2 = \frac{1\ \text{N}}{2\ \text{m/s}^2} = 0.5\ \text{kg}$

Step4: Solve Q8 identify physics law

The ball bounces up due to equal and opposite ground force, matching action-reaction law.

Answer:

1. C. 4 N
2. C. 20 N
3. A. The mass of the two rockets are the same.
4. C. the law of action-reaction