Question

if de = 6y - 80 and dg = y, find dg in parallelogram efgh.

Explanation:

Step1: Recall parallelogram property

In a parallelogram, the diagonals bisect each other. So, $DE = DG$.
$6y - 80=y$

Step2: Solve the equation for y

Subtract y from both sides: $6y - y-80=y - y$.
$5y-80 = 0$.
Then add 80 to both sides: $5y-80 + 80=0 + 80$.
$5y=80$.
Divide both sides by 5: $y=\frac{80}{5}=16$.

Step3: Find DG

Since $DG = y$, and $y = 16$, then $DG = 16$.

Answer:

16