Question

deltamath
← back to home
hw #11
date: february 11 at 11:01 pm
score: 0%
lines from point/slope (diagonal only)
score: 0/5 penalty: none
question
what is the equation of the line that passes through the point $(-7,8)$ and has a slope of $-1$?
show examples
answer attempt 1 out of 2
submit answer
lines from point/slope (diagonal only)
line equations from point/slope (point slope form)
standard to slope intercept form

Explanation:

Step1: Use point-slope formula

The point-slope form of a line is $y - y_1 = m(x - x_1)$, where $(x_1, y_1)=(-7,8)$ and $m=-1$.
$y - 8 = -1(x - (-7))$

Step2: Simplify the equation

Simplify the right-hand side and rearrange to slope-intercept form.
$y - 8 = -1(x + 7)$
$y - 8 = -x - 7$
$y = -x - 7 + 8$
$y = -x + 1$

Step3: (Optional) Convert to standard form (if needed)

To write in standard form $Ax + By = C$, rearrange the terms.
$x + y = 1$

Answer:

$y = -x + 1$ (or $x + y = 1$ in standard form)