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density worksheet 1 directions: solve the problem! show your work! this…

Question

density worksheet 1 directions: solve the problem! show your work! this is the basic problem given for understanding density. remember that the formula for density is... density = mass / volume volume = mass / density mass = density × volume 1. mass = 40g volume = 20ml what is the density? 2. mass = 35g density = 5 g/cm³ what is the volume? 3. density = 7 g/ml volume = 10ml what is the mass? 4. mass = 22g volume = 2cm³ what is the density? 5. mass = 16g density = 2 g/cm³ what is the volume? 6. density = 2 g/ml volume = 20ml what is the mass? 7. mass = 35g volume = 7cm³ what is the density? 8. mass = 70g density = 7 g/ml what is the volume? 9. density = 11 g/cm³ volume = 2cm³ what is the mass? 10. mass = 16g volume = 8ml what is the density?

Explanation:

Step1: Recall density - mass - volume formulas

The formulas are $D=\frac{M}{V}$, $V = \frac{M}{D}$, $M=D\times V$ where $D$ is density, $M$ is mass and $V$ is volume.

Step2: Solve problem 1

Given $M = 40g$ and $V=20mL$. Using $D=\frac{M}{V}$, we have $D=\frac{40g}{20mL}=2g/mL$.

Step3: Solve problem 2

Given $M = 35g$ and $D = 5g/cm^{3}$. Using $V=\frac{M}{D}$, we get $V=\frac{35g}{5g/cm^{3}} = 7cm^{3}$.

Step4: Solve problem 3

Given $D = 7g/mL$ and $V = 10mL$. Using $M=D\times V$, we obtain $M=7g/mL\times10mL = 70g$.

Step5: Solve problem 4

Given $M = 22g$ and $V = 2cm^{3}$. Using $D=\frac{M}{V}$, we find $D=\frac{22g}{2cm^{3}}=11g/cm^{3}$.

Step6: Solve problem 5

Given $M = 16g$ and $D = 2g/cm^{3}$. Using $V=\frac{M}{D}$, we have $V=\frac{16g}{2g/cm^{3}}=8cm^{3}$.

Step7: Solve problem 6

Given $D = 2g/mL$ and $V = 20mL$. Using $M=D\times V$, we get $M=2g/mL\times20mL = 40g$.

Step8: Solve problem 7

Given $M = 35g$ and $V = 7cm^{3}$. Using $D=\frac{M}{V}$, we obtain $D=\frac{35g}{7cm^{3}}=5g/cm^{3}$.

Step9: Solve problem 8

Given $M = 70g$ and $D = 7g/mL$. Using $V=\frac{M}{D}$, we find $V=\frac{70g}{7g/mL}=10mL$.

Step10: Solve problem 9

Given $D = 11g/cm^{3}$ and $V = 2cm^{3}$. Using $M=D\times V$, we have $M=11g/cm^{3}\times2cm^{3}=22g$.

Step11: Solve problem 10

Given $M = 16g$ and $V = 8mL$. Using $D=\frac{M}{V}$, we get $D=\frac{16g}{8mL}=2g/mL$.

Answer:

  1. $2g/mL$
  2. $7cm^{3}$
  3. $70g$
  4. $11g/cm^{3}$
  5. $8cm^{3}$
  6. $40g$
  7. $5g/cm^{3}$
  8. $10mL$
  9. $22g$
  10. $2g/mL$