QUESTION IMAGE
Question
describe the mistake made when solving $(x - 1)(3x^2 + 5x - 4)$ if lorrie got an answer of $3x^3 + 2x - x - 4$.
explain:
write the correct product below.
Explain:
To multiply \((x - 1)(3x^2 + 5x - 4)\), we use the distributive property (FOIL for polynomials). Lorrie's answer \(3x^3 + 2x - x - 4\) (assuming a typo, maybe \(3x^3 + 2x^2 - x - 4\) was intended) has a mistake in the middle terms. Let's do the correct multiplication:
- Distribute \(x\) to each term in \(3x^2 + 5x - 4\):
\(x \cdot 3x^2 = 3x^3\), \(x \cdot 5x = 5x^2\), \(x \cdot (-4) = -4x\).
- Distribute \(-1\) to each term in \(3x^2 + 5x - 4\):
\(-1 \cdot 3x^2 = -3x^2\), \(-1 \cdot 5x = -5x\), \(-1 \cdot (-4) = 4\).
- Combine like terms:
\(3x^3 + (5x^2 - 3x^2) + (-4x - 5x) + 4 = 3x^3 + 2x^2 - 9x + 4\).
Lorrie likely made a mistake in distributing \(-1\) to \(5x\) (got \(-x\) instead of \(-5x\)) and missed combining the \(x^2\) terms properly (or misapplied the distributive property to \(5x\) and \(3x^2\)).
Write the correct product below:
To find the correct product of \((x - 1)(3x^2 + 5x - 4)\):
Step 1: Distribute \(x\)
Multiply \(x\) by each term in \(3x^2 + 5x - 4\):
\(x \cdot 3x^2 = 3x^3\), \(x \cdot 5x = 5x^2\), \(x \cdot (-4) = -4x\).
Step 2: Distribute \(-1\)
Multiply \(-1\) by each term in \(3x^2 + 5x - 4\):
\(-1 \cdot 3x^2 = -3x^2\), \(-1 \cdot 5x = -5x\), \(-1 \cdot (-4) = 4\).
Step 3: Combine like terms
Add the results from Step 1 and Step 2:
\(3x^3 + 5x^2 - 4x - 3x^2 - 5x + 4\)
Combine \(x^2\) terms: \(5x^2 - 3x^2 = 2x^2\)
Combine \(x\) terms: \(-4x - 5x = -9x\)
Thus, the correct product is \(3x^3 + 2x^2 - 9x + 4\).
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Explain:
To multiply \((x - 1)(3x^2 + 5x - 4)\), we use the distributive property (FOIL for polynomials). Lorrie's answer \(3x^3 + 2x - x - 4\) (assuming a typo, maybe \(3x^3 + 2x^2 - x - 4\) was intended) has a mistake in the middle terms. Let's do the correct multiplication:
- Distribute \(x\) to each term in \(3x^2 + 5x - 4\):
\(x \cdot 3x^2 = 3x^3\), \(x \cdot 5x = 5x^2\), \(x \cdot (-4) = -4x\).
- Distribute \(-1\) to each term in \(3x^2 + 5x - 4\):
\(-1 \cdot 3x^2 = -3x^2\), \(-1 \cdot 5x = -5x\), \(-1 \cdot (-4) = 4\).
- Combine like terms:
\(3x^3 + (5x^2 - 3x^2) + (-4x - 5x) + 4 = 3x^3 + 2x^2 - 9x + 4\).
Lorrie likely made a mistake in distributing \(-1\) to \(5x\) (got \(-x\) instead of \(-5x\)) and missed combining the \(x^2\) terms properly (or misapplied the distributive property to \(5x\) and \(3x^2\)).
Write the correct product below:
To find the correct product of \((x - 1)(3x^2 + 5x - 4)\):
Step 1: Distribute \(x\)
Multiply \(x\) by each term in \(3x^2 + 5x - 4\):
\(x \cdot 3x^2 = 3x^3\), \(x \cdot 5x = 5x^2\), \(x \cdot (-4) = -4x\).
Step 2: Distribute \(-1\)
Multiply \(-1\) by each term in \(3x^2 + 5x - 4\):
\(-1 \cdot 3x^2 = -3x^2\), \(-1 \cdot 5x = -5x\), \(-1 \cdot (-4) = 4\).
Step 3: Combine like terms
Add the results from Step 1 and Step 2:
\(3x^3 + 5x^2 - 4x - 3x^2 - 5x + 4\)
Combine \(x^2\) terms: \(5x^2 - 3x^2 = 2x^2\)
Combine \(x\) terms: \(-4x - 5x = -9x\)
Thus, the correct product is \(3x^3 + 2x^2 - 9x + 4\).