Question

1. determine the equation in slope y-intercept form for the linear relation.

(3, 3) (6,1)
$\frac{1-3}{6-3}=\frac{-2}{-3}=\frac{2}{3}$
$y=\frac{2}{3}x + 5$
the coordinate points on the graph are (0, 5), (3, 3), (6, 1)

Explanation:

Step1: Identify slope formula

Slope $m = \frac{y_2 - y_1}{x_2 - x_1}$

Step2: Calculate slope with points

Use $(x_1,y_1)=(3,3)$ and $(x_2,y_2)=(6,1)$:
$m = \frac{1 - 3}{6 - 3} = \frac{-2}{3}$

Step3: Identify y-intercept

From the graph, the line crosses the y-axis at $(0,5)$, so $b=5$.

Step4: Write slope-intercept form

Substitute $m$ and $b$ into $y=mx+b$:
$y = -\frac{2}{3}x + 5$

Answer:

$y = -\frac{2}{3}x + 5$