Question

determine the intercepts of the line.
do not round your answers.

$y = 10x - 32$

y-intercept: $\left(\square, \square\
ight)$

x-intercept: $\left(\square, \square\
ight)$

your answer should be

• an integer, like 6
• a simplified proper fraction, like 3/5
• a simplified improper fraction, like 7/4

Explanation:

Step1: Find y-intercept (set x=0)

To find the y - intercept, we set \( x = 0 \) in the equation \( y=10x - 32 \).
Substituting \( x = 0 \) into the equation, we get \( y=10(0)-32 \).
Simplifying the right - hand side, \( 10\times0 = 0 \), so \( y=0 - 32=-32 \).
So the y - intercept is the point \( (0,-32) \).

Step2: Find x-intercept (set y=0)

To find the x - intercept, we set \( y = 0 \) in the equation \( y = 10x-32 \).
We get the equation \( 0=10x - 32 \).
First, add 32 to both sides of the equation: \( 10x=32 \).
Then, divide both sides by 10: \( x=\frac{32}{10}=\frac{16}{5} \).
So the x - intercept is the point \( (\frac{16}{5},0) \).

Answer:

y - intercept: \( (0, - 32) \)
x - intercept: \( (\frac{16}{5},0) \)