QUESTION IMAGE
Question
in the diagram below, $overline{ac}congoverline{ce}$ and $d$ is the mid - point of $overline{ce}$. if $ce = 10x + 18$, $de=7x - 1$, and $bc = 9x - 2$, find $ab$.
- classify $angle1$ and $angle2$ using all relationships that apply.
- classify $angle1$ and $angle2$ using all relationships that apply.
- if $mangle tuv=(9x + 1)^{circ}$, $mangle tuw=(7x - 9)^{circ}$, and $mangle wuv=(5x - 11)^{circ}$, find the value of $x$.
- find the value of $x$.
Step1: Find the value of \(x\) from the mid - point information
Since \(D\) is the mid - point of \(CE\), then \(CE = 2DE\). Given \(CE=10x + 18\) and \(DE = 7x-1\), we have the equation \(10x + 18=2(7x - 1)\).
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Step2: Find the lengths of \(AC\) and \(BC\)
First, find \(AC\). Since \(AC = CE\) and \(CE=10x + 18\), substituting \(x = 5\), we get \(CE=10\times5+18=50 + 18=68\), so \(AC = 68\).
Second, find \(BC\). Given \(BC=9x - 2\), substituting \(x = 5\), we get \(BC=9\times5-2=45-2 = 43\).
Step3: Find the length of \(AB\)
Since \(AC=AB + BC\), then \(AB=AC - BC\). Substituting \(AC = 68\) and \(BC = 43\), we get \(AB=68-43 = 25\).
for question 13:
Adjacent angles share a common side and a common vertex. Vertical angles are opposite angles formed by the intersection of two lines. Complementary angles add up to \(90^{\circ}\), supplementary angles add up to \(180^{\circ}\), and a linear pair is a pair of adjacent supplementary angles. For \(\angle1\) and \(\angle2\) in question 13, they are vertical angles as they are opposite angles formed by the intersection of two lines.
for question 14:
\(\angle1\) and \(\angle2\) share a common vertex and a common side, so they are adjacent. They are also complementary because the angle formed by the two intersecting lines is a right - angle, and \(\angle1+\angle2 = 90^{\circ}\).
for question 15:
Since \(m\angle TUV=m\angle TUW + m\angle WUV\), we have the equation \((9x + 1)=(7x-9)+(5x - 11)\).
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