Question

in the diagram below, what will the acceleration of the box be? 245 n 70 n 350 n 25 kg 245 n a 11.2 m/s² b 14 m/s² c 9.8 m/s² d 16.8 m/s²

Explanation:

Step1: Calculate net force in x - direction

The forces in the x - direction are $F_{1}=350N$ (right - hand side) and $F_{2}=70N$ (left - hand side). The net force in the x - direction $F_{net,x}=F_{1}-F_{2}$.
$F_{net,x}=350 - 70=280N$
The forces in the y - direction are $F_{y1}=245N$ (upward) and $F_{y2}=245N$ (downward). The net force in the y - direction $F_{net,y}=F_{y1}-F_{y2}=245 - 245 = 0N$. So the overall net force $F_{net}=F_{net,x}=280N$.

Step2: Use Newton's second law

Newton's second law is $F = ma$, where $F$ is the net force, $m$ is the mass, and $a$ is the acceleration. We know $F_{net}=280N$ and $m = 25kg$. We can solve for $a$ by rearranging the formula to $a=\frac{F_{net}}{m}$.
$a=\frac{280}{25}=11.2m/s^{2}$

Answer:

A. $11.2m/s^{2}$