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Question
difference of perfect squares (level 1)
score: 2/8 penalty: 1 off
question
factor completely.
49x² - 121
answer
attempt 1 out of 3
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Step1: Identify the form
The expression \(49x^2 - 121\) is a difference of perfect squares. The formula for factoring a difference of squares is \(a^2 - b^2=(a + b)(a - b)\).
Step2: Find \(a\) and \(b\)
For \(49x^2\), we have \(a = 7x\) because \((7x)^2 = 49x^2\). For \(121\), we have \(b = 11\) because \(11^2=121\).
Step3: Apply the formula
Using the difference of squares formula \(a^2 - b^2=(a + b)(a - b)\) with \(a = 7x\) and \(b = 11\), we get \((7x + 11)(7x - 11)\).
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\((7x + 11)(7x - 11)\)