Question

differentiate. y = 2x^3 - 2x^2 + x + 6. $\frac{dy}{dx}=square$

Explanation:

Step1: Apply power - rule to each term

$\frac{d}{dx}(2x^{3})=6x^{2}$, $\frac{d}{dx}(-2x^{2})=-4x$, $\frac{d}{dx}(x) = 1$, $\frac{d}{dx}(6)=0$

Step2: Sum up the derivatives

$6x^{2}-4x + 1$

Answer:

$6x^{2}-4x + 1$