Question

directions:

1. complete the description of the motion of each line segment.

extra practice problem #5
position vs. time
describe the speed and direction of object based on its graph.
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Explanation:

1. For the segment from 0 to 5 seconds: The position increases linearly with time, meaning the object moves away from the starting point at a constant speed. Calculate speed as $\frac{\text{Change in Position}}{\text{Change in Time}} = \frac{10\ \text{m}}{5\ \text{s}} = 2\ \text{m/s}$.
2. For the segment from 5 to 9 seconds: Position stays constant at 10 meters, so the object is not moving (at rest).
3. For the segment from 9 to 10 seconds: Position decreases linearly to 0, meaning the object moves back toward the starting point at a constant speed. Calculate speed as $\frac{\text{Change in Position}}{\text{Change in Time}} = \frac{10\ \text{m}}{1\ \text{s}} = 10\ \text{m/s}$.

Answer:

1. 0–5 seconds: Moving away at 2 m/s (constant speed)
2. 5–9 seconds: Stationary (no motion)
3. 9–10 seconds: Moving back at 10 m/s (constant speed)