Question

divide.
$\frac{23z^{4}+9z^{3}+18z^{2}}{3z^{2}}$
simplify your answer as much as possible.

Explanation:

Step1: Split the fraction

$\frac{23z^4 + 9z^3 + 18z^2}{3z^2} = \frac{23z^4}{3z^2} + \frac{9z^3}{3z^2} + \frac{18z^2}{3z^2}$

Step2: Simplify each term

For $\frac{23z^4}{3z^2}$: $\frac{23}{3}z^{4-2} = \frac{23}{3}z^2$
For $\frac{9z^3}{3z^2}$: $\frac{9}{3}z^{3-2} = 3z$
For $\frac{18z^2}{3z^2}$: $\frac{18}{3}z^{2-2} = 6$

Step3: Combine simplified terms

$\frac{23}{3}z^2 + 3z + 6$

Answer:

$\frac{23}{3}z^2 + 3z + 6$