Question

divide. if there is a remainder, include it as a simplified fraction.\\((-30y^{3}+35y^{2})div5y^{2}\\)

Explanation:

Step1: Divide each term by \(5y^2\)

We have \(\frac{-30y^3 + 35y^2}{5y^2}=\frac{-30y^3}{5y^2}+\frac{35y^2}{5y^2}\)

Step2: Simplify each fraction

For \(\frac{-30y^3}{5y^2}\), using the rule \(\frac{a^m}{a^n}=a^{m - n}\) and \(\frac{-30}{5}=-6\), we get \(-6y\). For \(\frac{35y^2}{5y^2}\), \(\frac{35}{5} = 7\) and \(\frac{y^2}{y^2}=1\), so it simplifies to \(7\).

Answer:

\(-6y + 7\)