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Question
dividing integers
now we can divide any integer by any other integer except 0. all we have to do is write
a fraction with the dividend (the number we are dividing into) as the numerator (top) and
the divisor (the number we are dividing by) as the denominator (bottom).
$10 \div 3 = \frac{10}{3}$
do each division problem. if the divisor goes evenly into the dividend, write your answer
as an integer. otherwise, write it as a fraction.
$12 \div -2 = -6$
$15 \div 3 =$
$15 \div 4 =$
$-8 \div -3 =$
$40 \div 7 = \frac{40}{7}$
$-7 \div 2 =$
$1 \div -6 =$
$54 \div 7 =$
$-3 \div 5 =$
$-45 \div -9 =$
$-7 \div 6 =$
$-2 \div 19 =$
a fraction can be positive or negative. to find the sign, just follow the rules for division.
when division is written using a fraction bar, the rules look like this:
$\frac{positive}{positive} = positive$
$\frac{negative}{positive} = negative$
$\frac{positive}{negative} = negative$
$\frac{negative}{negative} = positive$
if a fraction is positive, we will write it with no signs. if a fraction is negative, we will write it
with the negative sign on top.
$\frac{-3}{-4}$ is positive, so we will write $\frac{3}{4}$.
$\frac{3}{-4}$ is negative, so we will write $\frac{-3}{4}$.
do each division problem. write your answer as a positive or negative fraction.
$13 \div -3 = \frac{-13}{3}$
$-4 \div -7 =$
$15 \div -2 =$
$18 \div -5 =$
$-3 \div 10 =$
$1 \div -5 =$
$-1 \div 9 =$
$40 \div 29 =$
$-9 \div -10 =$
$9 \div -5 =$
$12 \div -7 =$
$-3 \div -100 =$
$12 \div 11 =$
$4 \div 5 =$
$-9 \div -14 =$
$-20 \div 7 =$
Step1: Solve first set (integer/fraction)
15 ÷ 3:
Divisor divides evenly.
$15\div3=5$
15 ÷ 4:
No even division, write as fraction.
$15\div4=\frac{15}{4}$
-8 ÷ -3:
Same sign = positive, no even division.
$-8\div-3=\frac{8}{3}$
-7 ÷ 2:
Different signs = negative, no even division.
$-7\div2=\frac{-7}{2}$
1 ÷ -6:
Different signs = negative, no even division.
$1\div-6=\frac{-1}{6}$
54 ÷ 7:
No even division, positive fraction.
$54\div7=\frac{54}{7}$
-3 ÷ 5:
Different signs = negative, no even division.
$-3\div5=\frac{-3}{5}$
-45 ÷ -9:
Same sign = positive, even division.
$-45\div-9=5$
-7 ÷ 6:
Different signs = negative, no even division.
$-7\div6=\frac{-7}{6}$
-2 ÷ 19:
Different signs = negative, no even division.
$-2\div19=\frac{-2}{19}$
Step2: Solve second set (signed fractions)
-4 ÷ -7:
Same sign = positive fraction.
$-4\div-7=\frac{4}{7}$
15 ÷ -2:
Different signs = negative fraction.
$15\div-2=\frac{-15}{2}$
18 ÷ -5:
Different signs = negative fraction.
$18\div-5=\frac{-18}{5}$
-3 ÷ 10:
Different signs = negative fraction.
$-3\div10=\frac{-3}{10}$
1 ÷ -5:
Different signs = negative fraction.
$1\div-5=\frac{-1}{5}$
-1 ÷ 9:
Different signs = negative fraction.
$-1\div9=\frac{-1}{9}$
40 ÷ 29:
Same sign = positive fraction.
$40\div29=\frac{40}{29}$
-9 ÷ -10:
Same sign = positive fraction.
$-9\div-10=\frac{9}{10}$
9 ÷ -5:
Different signs = negative fraction.
$9\div-5=\frac{-9}{5}$
12 ÷ -7:
Different signs = negative fraction.
$12\div-7=\frac{-12}{7}$
-3 ÷ -100:
Same sign = positive fraction.
$-3\div-100=\frac{3}{100}$
12 ÷ 11:
Same sign = positive fraction.
$12\div11=\frac{12}{11}$
4 ÷ 5:
Same sign = positive fraction.
$4\div5=\frac{4}{5}$
-9 ÷ -14:
Same sign = positive fraction.
$-9\div-14=\frac{9}{14}$
-20 ÷ 7:
Different signs = negative fraction.
$-20\div7=\frac{-20}{7}$
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First set (completed):
$12\div-2=-6$, $15\div3=5$, $15\div4=\frac{15}{4}$, $-8\div-3=\frac{8}{3}$
$40\div7=\frac{40}{7}$, $-7\div2=\frac{-7}{2}$, $1\div-6=\frac{-1}{6}$, $54\div7=\frac{54}{7}$
$-3\div5=\frac{-3}{5}$, $-45\div-9=5$, $-7\div6=\frac{-7}{6}$, $-2\div19=\frac{-2}{19}$
Second set (completed):
$13\div-3=\frac{-13}{3}$, $-4\div-7=\frac{4}{7}$, $15\div-2=\frac{-15}{2}$, $18\div-5=\frac{-18}{5}$
$-3\div10=\frac{-3}{10}$, $1\div-5=\frac{-1}{5}$, $-1\div9=\frac{-1}{9}$, $40\div29=\frac{40}{29}$
$-9\div-10=\frac{9}{10}$, $9\div-5=\frac{-9}{5}$, $12\div-7=\frac{-12}{7}$, $-3\div-100=\frac{3}{100}$
$12\div11=\frac{12}{11}$, $4\div5=\frac{4}{5}$, $-9\div-14=\frac{9}{14}$, $-20\div7=\frac{-20}{7}$