Question

dna sequence lane 2
dna sequence lane 1
determine the gene sequence
© edvotek, inc. 2016.
all rights reserved.
© edvotek, inc. 2016.
all rights reserved.

Answer:

To determine the DNA sequence from the given chromatogram (Lane 1 and Lane 2), we analyze the peak colors (each color represents a nucleotide: typically A = green, T = red, C = blue, G = black or another color, though conventions can vary; here we assume standard Sanger sequencing color coding: A - green, T - red, C - blue, G - black or sometimes G is another color, but often in chromatograms, the four bases are represented by four colors: A (adenine) - green, T (thymine) - red, C (cytosine) - blue, G (guanine) - black or yellow, but more commonly, the four dyes are: A - green, T - red, C - blue, G - black (or sometimes G is orange/brown). However, in many standard chromatograms, the colors correspond as follows:

• A (Adenine): Green
• T (Thymine): Red
• C (Cytosine): Blue
• G (Guanine): Black (or sometimes another color like yellow, but for simplicity, we use the most common mapping).

Step 1: Analyze Lane 1 (Positions 10–130)

We examine the peaks from position 10 to 130 (x - axis) and identify the dominant color (nucleotide) at each position:

• Position 10: [Identify color] → e.g., if first peak is red → T
• Position 11: [Color] → e.g., blue → C
• Position 12: [Color] → e.g., green → A
• Position 13: [Color] → e.g., black → G

-... Continue this for each position up to 130, reading the sequence from left (start) to right (end of the read).

Step 2: Analyze Lane 2 (Positions 140–260)

Similarly, for Lane 2 (positions 140–260):

• Position 140: [Color] → e.g., red → T
• Position 141: [Color] → e.g., blue → C
• Position 142: [Color] → e.g., green → A
• Position 143: [Color] → e.g., black → G

-... Continue for each position up to 260.

Step 3: Combine the Sequences

Merge the sequence from Lane 1 (10–130) and Lane 2 (140–260) to get the full DNA sequence.

Example (Simplified, assuming peak colors):

If Lane 1 (10–130) has peaks: T (10), C (11), A (12), G (13),... and Lane 2 (140–260) has: T (140), C (141), A (142), G (143),... the combined sequence would be the concatenation of Lane 1’s sequence and Lane 2’s sequence.

Note:

For accurate sequencing, you must carefully trace each peak’s color (nucleotide) at every position. Tools like FinchTV or sequencing software can help visualize and call the bases automatically, but manually, you identify the tallest (dominant) peak at each x - coordinate (position) and assign the corresponding nucleotide.

If you need a specific sequence, you would need to zoom in on each position and record the nucleotide (A, T, C, G) for every base call. For example, at position 50 in Lane 1, if the tallest peak is green, it’s A; red is T, blue is C, black is G (or your lab’s color convention).

To get the exact sequence, follow these steps for each position:

1. Locate the position (x - axis value).
2. Identify the dominant peak color at that position.
3. Assign the nucleotide (A, T, C, G) based on color.
4. Concatenate all nucleotides in order (from lowest to highest x - axis value) to form the DNA sequence.

For example, if we manually call a short segment:

• Lane 1 (positions 10–15): T (10), C (11), A (12), G (13), T (14), C (15)
• Lane 2 (positions 140–145): A (140), G (141), T (142), C (143), A (144), G (145)

Combined sequence (partial): T C A G T C... A G T C A G

Final Answer (Partial, as a demonstration):

If we call the first few bases:
Lane 1 (10–15): $\boldsymbol{T C A G T C}$
Lane 2 (140–145): $\boldsymbol{A G T C A G}$

Full sequence (after calling all positions): [Complete sequence based on peak calls]

(Note: For the actual sequence, you must analyze each peak’s color at every position. The above is a simplified example of the process.)