QUESTION IMAGE
Question
drag and drop the options to complete the punnett square based on the information below. use the information to answer the questions. humans can inherit a \hitchhikers thumb\ which is a recessive trait. cross a parent with a genotype of tt and a parent with a genotype of tt below. what are the f₁ genotype possibilities? what percentage will be heterozygous? is there a chance of any offspring inheriting the hitchhikers thumb? options: yes, tt and tt, tt, 50%, tt, t, t, 100%, no
Completing the Punnett Square:
- Top Row (Parent Tt's gametes): The parent with genotype \( Tt \) can produce gametes \( T \) and \( t \). The parent with genotype \( tt \) can only produce gametes \( t \) and \( t \). So the top two boxes (above the Punnett square) should be \( T \) and \( t \) (from the \( Tt \) parent), and the left - hand column (from the \( tt \) parent) should be \( t \) and \( t \).
- The first empty box in the Punnett square (top - right) when we cross \( T \) (from top) and \( t \) (from left) is already filled as \( Tt \)? Wait, no, let's re - do. Wait, the first parent is \( Tt \) (so gametes \( T \) and \( t \)) and the second is \( tt \) (gametes \( t \) and \( t \)). So the Punnett square should be:
- Top row (gametes from \( Tt \)): \( T \), \( t \)
- Left column (gametes from \( tt \)): \( t \), \( t \)
- Then the four cells:
- Top - left: \( T\times t=Tt \)
- Top - right: \( t\times t = tt \)
- Bottom - left: \( T\times t=Tt \)
- Bottom - right: \( t\times t = tt \)
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ing the Questions:
1. What are the \( F_1 \) genotype possibilities?
The possible genotypes of the offspring (\( F_1 \)) are \( Tt \) and \( tt \).
2. What percentage will be heterozygous?
Heterozygous genotype is \( Tt \). From the Punnett square, out of 4 possible offspring, 2 have genotype \( Tt \). The percentage is calculated as \( \frac{2}{4}\times100 = 50\% \).
3. Is there a chance of any offspring inheriting the hitchhiker's thumb?
Hitchhiker's thumb is a recessive trait, so it is expressed when the genotype is \( tt \). Since we have \( tt \) as a possible genotype of the offspring, the answer is Yes.
Final Answers:
- \( F_1 \) genotype possibilities: \( Tt \) and \( tt \)
- Percentage heterozygous: \( 50\% \)
- Chance of inheriting hitchhiker's thumb: Yes