Question

b. draw a net of the square pyramid including dimensions. c. find the surface area of the square pyramid.

Explanation:

Step1: Identify base and triangle areas

The base is a square with side length $s = 10$ ft, so its area $A_{base}=s^{2}=10^{2}=100$ square - feet. Each triangular face has a base $b = 10$ ft and a height $h = 10$ ft. The area of a triangle is $A_{triangle}=\frac{1}{2}bh$.

Step2: Calculate area of one triangular face

$A_{triangle}=\frac{1}{2}\times10\times10 = 50$ square - feet.

Step3: Calculate total area of triangular faces

There are 4 triangular faces. So the total area of the triangular faces $A_{triangles}=4\times A_{triangle}=4\times50 = 200$ square - feet.

Step4: Calculate surface area

The surface area $A$ of the square - pyramid is the sum of the area of the base and the total area of the triangular faces. $A=A_{base}+A_{triangles}=100 + 200=300$ square - feet.

Answer:

300 square feet