Question

due sep 19 by 11:59pm points 30 submitting an external tool available sep 11 at 12am - oct 24 at 11:59pm
f(x)=\begin{cases}x + 6&\text{for }x < - 5\\-5&\text{for }x=-5\\-(x + 5)^2+1&\text{for }x > - 5end{cases}find (f(-6)) answer attempt 1 out of 2 submit answer undefined

Explanation:

Step1: Determine the function part

Since -6 < - 5, we use the first - part of the piece - wise function $f(x)=x + 6$.

Step2: Substitute the value

Substitute $x=-6$ into $f(x)=x + 6$. So $f(-6)=-6 + 6$.

Step3: Calculate the result

$-6+6 = 0$.

Answer:

$0$