Question

for each part below, solve the equation.
(a) solve for u.
$6(u - 2)+2 = 2(3u - 5)$
no solution
$u = \square$
all real numbers are solutions
(b) solve for y.
$-8(y + 1)=2(1 - 4y)-9$
no solution
$y = \square$
all real numbers are solutions

Explanation:

Step1: Expand both sides (part a)

$6u - 12 + 2 = 6u - 10$

Step2: Simplify both sides (part a)

$6u - 10 = 6u - 10$

Step3: Rearrange terms (part a)

$6u - 6u = -10 + 10$
$0 = 0$

Step4: Expand both sides (part b)

$-8y - 8 = 2 - 8y - 9$

Step5: Simplify both sides (part b)

$-8y - 8 = -8y - 7$

Step6: Rearrange terms (part b)

$-8y + 8y = -7 + 8$
$0 = 1$

Answer:

(a) All real numbers are solutions
(b) No solution