Question

each of two parents has the genotype brown/green, which consists of the pair of alleles that determine eye color, and each parent contributes one of those alleles to a child. assume that if the child has at least one brown allele, that color will dominate and the child’s eye color will be brown.
a. list the different possible outcomes. assume that these outcomes are equally likely.
b. what is the probability that a child of these parents will have the green/green genotype?
c. what is the probability that the child will have brown eye color?

a. list the possible outcomes.
a. brown/brown and green/green
b. brown/green and green/brown
c. brown/brown, brown/green, green/brown, and green/green
d. brown/brown, brown/green, and green/green

b. the probability that a child of these parents will have the green/green genotype is \boxed{} (round to two decimal places as needed.)

Explanation:

Part a

Each parent has alleles brown (B) and green (g). When they contribute alleles to a child, the possible combinations are: parent 1 gives B and parent 2 gives B (brown/brown), parent 1 gives B and parent 2 gives g (brown/green), parent 1 gives g and parent 2 gives B (green/brown), parent 1 gives g and parent 2 gives g (green/green). So the correct option is C.

Step1: Identify total outcomes

From part a, we know there are 4 possible outcomes (brown/brown, brown/green, green/brown, green/green), and they are equally likely.

Step2: Identify favorable outcomes

The favorable outcome for green/green genotype is 1 (only green/green).

Step3: Calculate probability

Probability is the number of favorable outcomes divided by total outcomes. So probability $= \frac{1}{4} = 0.25$.

Step1: Identify total outcomes

Total possible outcomes are 4 (from part a).

Step2: Identify favorable outcomes for brown eyes

Brown eyes occur when there is at least one brown allele. The genotypes with at least one brown allele are brown/brown, brown/green, green/brown. So there are 3 favorable outcomes.

Step3: Calculate probability

Probability $= \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{3}{4} = 0.75$.

Answer:

C. brown/brown, brown/green, green/brown, and green/green

Part b