Question

estimate the sum. round each number to the nearest whole number, then add.
$7 \frac{20}{89} + 1 \frac{3}{10}$
the sum is approximately \boxed{
submit

Explanation:

Step1: Round \(7\frac{20}{89}\) to nearest whole number

To round a mixed number \(a\frac{b}{c}\) to the nearest whole number, we check the fraction \(\frac{b}{c}\). If \(\frac{b}{c} \geq 0.5\), we round up, else we round down.

For \(7\frac{20}{89}\), calculate \(\frac{20}{89}\approx0.225\) (since \(20\div89\approx0.225\)). Since \(0.225< 0.5\), we round \(7\frac{20}{89}\) down to \(7\).

Step2: Round \(1\frac{3}{10}\) to nearest whole number

For \(1\frac{3}{10}\), the fraction is \(\frac{3}{10} = 0.3\). Since \(0.3<0.5\), we round \(1\frac{3}{10}\) down to \(1\).

Step3: Add the rounded numbers

Now we add the rounded numbers: \(7 + 1=8\).

Answer:

\(8\)