Question

estimate the sum. round each number to the nearest whole number, then add.
$1 \frac{41}{59} + 6 \frac{13}{84}$
the sum is approximately \boxed{}.

Explanation:

Step1: Round \(1\frac{41}{59}\) to nearest whole number

The fraction \(\frac{41}{59}\) is greater than \(\frac{1}{2}\) (since \(41> 59\div2 = 29.5\)), so \(1\frac{41}{59}\approx2\).

Step2: Round \(6\frac{13}{84}\) to nearest whole number

The fraction \(\frac{13}{84}\) is less than \(\frac{1}{2}\) (since \(13<84\div2 = 42\)), so \(6\frac{13}{84}\approx6\).

Step3: Add the rounded numbers

Add the two rounded whole numbers: \(2 + 6=8\).

Answer:

\(8\)