Question

estimate the sum. round each number to the nearest whole number, then add.
$6\frac{3}{5} + 3\frac{1}{16}$
the sum is approximately \boxed{}.

Explanation:

Step1: Round \(6\frac{3}{5}\) to nearest whole number

Convert \(6\frac{3}{5}\) to decimal: \(6\frac{3}{5}=6 + \frac{3}{5}=6 + 0.6 = 6.6\). The nearest whole number to \(6.6\) is \(7\) (since \(0.6\geq0.5\)).

Step2: Round \(3\frac{1}{16}\) to nearest whole number

Convert \(3\frac{1}{16}\) to decimal: \(\frac{1}{16}=0.0625\), so \(3\frac{1}{16}=3 + 0.0625 = 3.0625\). The nearest whole number to \(3.0625\) is \(3\) (since \(0.0625<0.5\)).

Step3: Add the rounded numbers

Add \(7\) and \(3\): \(7 + 3 = 10\).

Answer:

\(10\)