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evaluate: \\(\\log_{12}12\\) \\(\\circ\\) 0 \\(\\circ\\) 1 \\(\\circ\\)…

Question

evaluate: \\(\log_{12}12\\) \\(\circ\\) 0 \\(\circ\\) 1 \\(\circ\\) 12 \\(\circ\\) -1 done

Explanation:

Step1: Recall the logarithm identity

The logarithm identity states that for any positive number \( a \) (where \( a
eq 1 \)), \( \log_{a}a = 1 \). This is because the logarithm \( \log_{a}x \) represents the exponent to which we must raise \( a \) to get \( x \). In this case, we need to find the exponent \( y \) such that \( 12^{y}=12 \).

Step2: Solve for the exponent

We know that \( 12^{1}=12 \). So, by the definition of a logarithm, \( \log_{12}12 = 1 \).

Answer:

1