Question

evaluate the following permutation: 6p3

Explanation:

Step1: Recall permutation formula

The formula for permutations is $_{n}P_{r}=\frac{n!}{(n - r)!}$. Here $n = 6$ and $r=3$.

Step2: Calculate factorial values

$n!=n\times(n - 1)\times\cdots\times1$. So $6! = 6\times5\times4\times3\times2\times1=720$ and $(6 - 3)!=3!=3\times2\times1 = 6$.

Step3: Substitute values into formula

$_{6}P_{3}=\frac{6!}{(6 - 3)!}=\frac{720}{6}=120$.

Answer:

120