Question

evaluate $y = e^x + 1$ for the following values of $x$. round to the nearest thousandth. $x = -2, y \approx \square$ $x = 1, y \approx \square$ $x = 2, y \approx \square$

Explanation:

Step1: Substitute $x=-2$ into the function

$y = e^{-2} + 1 = \frac{1}{e^2} + 1$
Calculate $e^2 \approx 7.38906$, so $\frac{1}{7.38906} + 1 \approx 0.1353 + 1 = 1.1353$
Round to nearest thousandth: $1.135$

Step2: Substitute $x=1$ into the function

$y = e^{1} + 1$
Calculate $e^1 \approx 2.71828$, so $2.71828 + 1 = 3.71828$
Round to nearest thousandth: $3.718$

Step3: Substitute $x=2$ into the function

$y = e^{2} + 1$
Calculate $e^2 \approx 7.38906$, so $7.38906 + 1 = 8.38906$
Round to nearest thousandth: $8.389$

Answer:

$x=-2, y \approx 1.135$
$x=1, y \approx 3.718$
$x=2, y \approx 8.389$