Question

evaluate the function for the given value of x.
$h(x) = -3x^4 + 2x^3 - 12x - 6$; $x = -2$
$h(-2) = \square$

Explanation:

Step1: Substitute $x=-2$ into $h(x)$

$h(-2) = -3(-2)^4 + 2(-2)^3 - 12(-2) - 6$

Step2: Calculate each power term

$(-2)^4=16$, $(-2)^3=-8$
$h(-2) = -3(16) + 2(-8) - 12(-2) - 6$

Step3: Compute each multiplication

$-3(16)=-48$, $2(-8)=-16$, $-12(-2)=24$
$h(-2) = -48 - 16 + 24 - 6$

Step4: Perform arithmetic operations

$h(-2) = (-48-16) + (24-6) = -64 + 18$

Answer:

$-46$