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for every 1 molecule of glucose (c6h12o6) and 6 molecules of oxygen gas…

Question

for every 1 molecule of glucose (c6h12o6) and 6 molecules of oxygen gas (o2) that go into cellular respiration, the process produces 6 molecules of carbon dioxide gas (co2) and 6 molecules of water (h2o). complete the table.
type of atom: h, c, o
number of atoms in 6 molecules of carbon dioxide: 0, 6,
number of atoms in 6 molecules of water:
total number of atoms in products:

Explanation:

Step1: Analyze carbon - dioxide formula

The formula for carbon - dioxide is $CO_2$. For 6 molecules of $CO_2$, the number of carbon atoms is 6 (since each $CO_2$ has 1 C atom), and the number of oxygen atoms is $6\times2 = 12$.

Step2: Analyze water formula

The formula for water is $H_2O$. For 6 molecules of $H_2O$, the number of hydrogen atoms is $6\times2=12$, and the number of oxygen atoms is 6.

Step3: Calculate total atoms in products

Total number of carbon atoms in products = 6 (from $CO_2$). Total number of hydrogen atoms in products = 12 (from $H_2O$). Total number of oxygen atoms in products = 12 (from $CO_2$)+6 (from $H_2O$) = 18.

Answer:

Type of atomNumber of atoms in 6 molecules of carbon dioxideNumber of atoms in 6 molecules of waterTotal number of atoms in products
H01212
O12618