Question

every person has blood type o, a, b, or ab. a random group of people are blood - typed, and the results are shown in the table. use the table to determine the following probabilities. the probability that a randomly chosen person from this group has type b is . the probability that a randomly chosen person from this group has type ab is . the probability that a randomly chosen person from this group has type b or type ab blood is . blood type number of people o 22 a 20 b 6 ab 2

Explanation:

Step1: Calculate total number of people

$22 + 20+6 + 2=50$

Step2: Calculate probability of type B

The probability formula is $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. For type B, the number of favorable outcomes is 6 and total is 50. So $P(B)=\frac{6}{50}=\frac{3}{25}$

Step3: Calculate probability of type AB

For type AB, the number of favorable outcomes is 2 and total is 50. So $P(AB)=\frac{2}{50}=\frac{1}{25}$

Step4: Calculate probability of type B or type AB

Using the addition - rule for mutually - exclusive events $P(B\cup AB)=P(B)+P(AB)$. Substitute $P(B)=\frac{3}{25}$ and $P(AB)=\frac{1}{25}$, we get $P(B\cup AB)=\frac{3 + 1}{25}=\frac{4}{25}$

Answer:

The probability that a randomly chosen person from this group has type B is $\frac{3}{25}$.
The probability that a randomly chosen person from this group has type AB is $\frac{1}{25}$.
The probability that a randomly chosen person from this group has type B or type AB blood is $\frac{4}{25}$.