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examples 5 and 6 suppose m is the mid - point of (overline{fg}). find e…

Question

examples 5 and 6
suppose m is the mid - point of (overline{fg}). find each missing measure.

  1. (fm = 5y + 13, mg = 5 - 3y, fg=?)
  2. (fm = 3x - 4, mg = 5x - 26, fg =?)
  3. (fm = 8a + 1, fg = 42, a =?)
  4. (mg = 7x - 15, fg = 33, x =?)
  5. (fm = 3n + 1, mg = 6 - 2n, fg =?)
  6. (fm = 12x - 4, mg = 5x + 10, fg =?)
  7. (fm = 2k - 5, fg = 18, k =?)
  8. (fg = 14a + 1, fm = 14.5, a =?)
  9. (mg = 13x + 1, fg = 15, x =?)
  10. (fg = 11x - 15.6, mg = 10.9, x =?)

mixed exercises
find the coordinates of the missing endpoint if p is the mid - point of (overline{nq}).

  1. (n(2,0),p(5,2))
  2. (n(5,4),p(6,3))
  3. (q(3,9),p(-1,5))

Explanation:

Response
39.

Step1: Use mid - point property

Since \(M\) is the mid - point of \(\overline{FG}\), then \(FM = MG\). So, \(5y + 13=5 - 3y\).

Step2: Solve for \(y\)

Add \(3y\) to both sides: \(5y+3y + 13=5-3y + 3y\), which gives \(8y+13 = 5\). Then subtract 13 from both sides: \(8y+13 - 13=5 - 13\), so \(8y=-8\). Divide both sides by 8: \(y=-1\).

Step3: Find \(FM\) and \(MG\)

Substitute \(y = - 1\) into \(FM\): \(FM=5(-1)+13=8\). Substitute \(y=-1\) into \(MG\): \(MG = 5-3(-1)=8\).

Step4: Find \(FG\)

Since \(FG=FM + MG\), then \(FG=8 + 8=16\).

Step1: Use mid - point property

Since \(M\) is the mid - point of \(\overline{FG}\), \(FM = MG\). So, \(3x - 4=5x - 26\).

Step2: Solve for \(x\)

Subtract \(3x\) from both sides: \(3x-3x - 4=5x-3x - 26\), which gives \(-4 = 2x-26\). Add 26 to both sides: \(-4 + 26=2x-26 + 26\), so \(22 = 2x\). Divide both sides by 2: \(x = 11\).

Step3: Find \(FM\) and \(MG\)

Substitute \(x = 11\) into \(FM\): \(FM=3(11)-4=29\). Substitute \(x = 11\) into \(MG\): \(MG=5(11)-26=29\).

Step4: Find \(FG\)

Since \(FG=FM + MG\), then \(FG=29+29 = 58\).

Step1: Use mid - point property

Since \(M\) is the mid - point of \(\overline{FG}\), \(FG = 2FM\). Given \(FM=8a + 1\) and \(FG = 42\), we have \(42=2(8a + 1)\).

Step2: Solve the equation

First, distribute on the right - hand side: \(42=16a+2\). Subtract 2 from both sides: \(42 - 2=16a+2 - 2\), so \(40 = 16a\). Divide both sides by 16: \(a=\frac{40}{16}=\frac{5}{2}=2.5\).

Answer:

\(FG = 16\)

40.