Question

exit ticket in-class practice 1. find tan d and tan e. write each answer as a fraction and as a decimal.

Explanation:

Step1: Recall tangent ratio definition

For an acute angle in a right triangle, $\tan(\theta) = \frac{\text{opposite side}}{\text{adjacent side}}$

Step2: Identify sides for $\tan D$

Opposite to $\angle D$ is $12$, adjacent is $20$.
$\tan D = \frac{12}{20} = \frac{3}{5} = 0.6$

Step3: Identify sides for $\tan E$

Opposite to $\angle E$ is $20$, adjacent is $12$.
$\tan E = \frac{20}{12} = \frac{5}{3} \approx 1.67$

Answer:

$\tan D = \frac{3}{5}$ (or $0.6$)
$\tan E = \frac{5}{3}$ (or approximately $1.67$)