Question

an exposure is made using 100 milliamperes (ma) and 0.05 seconds (s). how will the beam intensity change if the exposure is repeated using 200 ma and 0.025 s?
beam intensity increases
beam intensity decreases
beam intensity remains the same

Explanation:

Step1: Calculate the first mAs value

The product of milliamperes (mA) and seconds (s) is called mAs, which is related to beam - intensity. For the first exposure, $mAs_1=100\times0.05 = 5$ mAs.

Step2: Calculate the second mAs value

For the second exposure, $mAs_2 = 200\times0.025=5$ mAs.

Step3: Analyze the change in beam intensity

Since $mAs_1 = mAs_2$, the beam intensity remains the same.

Answer:

Beam intensity remains the same