Question

express 9.2 - 3\sqrt{-8} as a complex number in the form of a + bi. what is the imaginary term? (1

Explanation:

Step1: Simplify the square - root of a negative number

We know that $\sqrt{-8}=\sqrt{8}\times\sqrt{-1}$. Since $\sqrt{-1}=i$ and $\sqrt{8}=\sqrt{4\times2}=2\sqrt{2}$, then $\sqrt{-8}=2\sqrt{2}i$.

Step2: Rewrite the given expression as a complex number

The given expression is $9.2 - 3\sqrt{-8}$. Substituting $\sqrt{-8}=2\sqrt{2}i$ into it, we get $9.2-3\times2\sqrt{2}i=9.2 - 6\sqrt{2}i$.

Answer:

The imaginary term is $- 6\sqrt{2}$