Question

express the trig ratios as fractions in simplest terms.
answer attempt 1 out of 8
sin r =
cos q =
sin r and cos q .

Explanation:

Step1: Recall sine definition

For angle $R$, $\sin R = \frac{\text{opposite side}}{\text{hypotenuse}}$
$\sin R = \frac{PQ}{QR} = \frac{16}{17}$

Step2: Recall cosine definition

For angle $Q$, $\cos Q = \frac{\text{adjacent side}}{\text{hypotenuse}}$
$\cos Q = \frac{PQ}{QR} = \frac{16}{17}$

Step3: Compare the two values

Both ratios equal $\frac{16}{17}$, so they are equal.

Answer:

$\sin R = \frac{16}{17}$
$\cos Q = \frac{16}{17}$
$\sin R$ and $\cos Q$ are equal