Question

the expression $\frac{1}{2}(b_1 + b_2)$ gives the area of a trapezoid with height. 9 in. 16 in. area: in²

Explanation:

Step1: Identify values

Let $h$ be the height, $b_1$ and $b_2$ be the bases. Here $h = 8$ in, $b_1=9$ in, $b_2 = 16$ in.

Step2: Substitute into formula

The area formula of a trapezoid is $A=\frac{1}{2}h(b_1 + b_2)$. Substitute the values: $A=\frac{1}{2}\times8\times(9 + 16)$.

Step3: First calculate inside parentheses

$9+16=25$. So the expression becomes $A=\frac{1}{2}\times8\times25$.

Step4: Calculate $\frac{1}{2}\times8$

$\frac{1}{2}\times8 = 4$. Then $A=4\times25$.

Step5: Final - calculation

$4\times25 = 100$.

Answer:

$100$