Question

factor\
k² - 2k - 24\
(k+6)(k-1)\
(k+4)(k-6)\
(k-4)(k+6)\
(k+4)(k+6)

Explanation:

Step1: Recall factoring quadratic formula

For a quadratic \(k^2 + bk + c\), we find two numbers that multiply to \(c\) and add to \(b\). Here, quadratic is \(k^2 - 2k - 24\), so we need two numbers with product \(-24\) and sum \(-2\).

Step2: Find the two numbers

Numbers \(4\) and \(-6\): \(4\times(-6)=-24\) and \(4 + (-6)=-2\).

Step3: Factor the quadratic

Using these numbers, we write the quadratic as \((k + 4)(k - 6)\) since \((k + 4)(k - 6)=k^2 - 6k + 4k - 24 = k^2 - 2k - 24\).

Answer:

B. \((k + 4)(k - 6)\)