Question

factor completely.
14y + 12y³ + 6y² + 7

Explanation:

Step1: Rearrange terms by degree

$12y^3 + 6y^2 + 14y + 7$

Step2: Group into two pairs

$(12y^3 + 6y^2) + (14y + 7)$

Step3: Factor out GCF from each pair

$6y^2(2y + 1) + 7(2y + 1)$

Step4: Factor out common binomial

$(2y + 1)(6y^2 + 7)$

Answer:

$(2y + 1)(6y^2 + 7)$