Question

factor completely. 27w³ + 15w² + 45w + 25

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(27w^3 + 15w^2) + (45w + 25)$

Step2: Factor out GCF from each group

Factor out $3w^2$ from the first group and $5$ from the second group: $3w^2(9w + 5) + 5(9w + 5)$

Step3: Factor out the common binomial factor

Factor out $(9w + 5)$: $(3w^2 + 5)(9w + 5)$

Answer:

$(3w^2 + 5)(9w + 5)$