Question

factor completely.
$2g^3 - 2g^2 - 9g + 9$

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: \((2g^3 - 2g^2) + (-9g + 9)\)

Step2: Factor out the GCF from each group

Factor out \(2g^2\) from the first group and \(-9\) from the second group: \(2g^2(g - 1) - 9(g - 1)\)

Step3: Factor out the common binomial factor

Factor out \((g - 1)\) from both terms: \((g - 1)(2g^2 - 9)\)

Answer:

\((g - 1)(2g^2 - 9)\)