Question

factor by grouping.
$3w^3 + 2w^2 + 15w + 10$

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(3w^3 + 2w^2) + (15w + 10)$

Step2: Factor out GCF from each group

Factor out $w^2$ from the first group and $5$ from the second group: $w^2(3w + 2) + 5(3w + 2)$

Step3: Factor out the common binomial factor

Factor out $(3w + 2)$: $(3w + 2)(w^2 + 5)$

Answer:

$(3w + 2)(w^2 + 5)$