QUESTION IMAGE
Question
factor label method
example: it takes 0.173 days for light to travel from the sun to the closest planet in our solar system, mercury. how many seconds does it take?
- write down the ku (known unit) measurement your calculated answer will depend on: 0.173 days
- write down the conversion factors needed to take your given measurement and get to your end answer:
days → hours → minutes → seconds
1 day = 24 hours
1 hour = 60 minutes
1 minute = 60 seconds
- write out your factor label method calculations and circle your final answer. write down all steps:
( 0.173 \text{ days} \times left( \frac{24 \text{ hr}}{1 \text{ day}}
ight) \times left( \frac{60 \text{ min}}{1 \text{ hr}}
ight) \times left( \frac{60 \text{ sec}}{1 \text{ min}}
ight) = )
( 0.173 \text{ days} \times left( \frac{24 \text{ hr}}{1 \text{ day}}
ight) \times left( \frac{60 \text{ min}}{1 \text{ hr}}
ight) \times left( \frac{60 \text{ sec}}{1 \text{ min}}
ight) = 14900 \text{ seconds} ) (rounded to 3 sig figs because 0.173 days has 3 sig figs)
- the distance between trappist-1 solar system (a system with 7 earth-like planets) and earth is 39.0 light years. how many calendar years would it take for nasa’s space shuttle to get there at 17,500 miles per hour?
- the external tank for the space shuttle carried 143,000 gallons of liquid oxygen. a gallon of liquid oxygen weighs 4.322 kg. nasa paid $2.6 per kg for liquid oxygen. how much did nasa spend in total on liquid oxygen for the external space shuttle tank, for one mission?
(c) bethany lau
Problem 2: Time to Travel to Trappist - 1
Step 1: Recall the speed of light and convert light - years to miles
The speed of light \(c = 186000\) miles per second. One light - year is the distance light travels in one year.
First, find the number of seconds in a year:
- Number of hours in a year: \(365\) days/year\(\times24\) hours/day \( = 8760\) hours/year
- Number of minutes in a year: \(8760\) hours/year\(\times60\) minutes/hour \(= 525600\) minutes/year
- Number of seconds in a year: \(525600\) minutes/year\(\times60\) seconds/minute \( = 31536000\) seconds/year
The distance of one light - year \(d_{ly}=186000\) miles/second\(\times31536000\) seconds/year\(=5.865696\times 10^{12}\) miles/year
The distance to Trappist - 1 is \(d = 39.0\) light - years. So the total distance \(D=39.0\times5.865696\times 10^{12}\) miles \(=2.28762144\times 10^{14}\) miles
Step 2: Use the formula \(t=\frac{D}{v}\) to find the time in hours
The speed of the space shuttle \(v = 17500\) miles per hour.
\(t=\frac{2.28762144\times 10^{14}\text{ miles}}{17500\text{ miles/hour}}\)
\(t=\frac{2.28762144\times 10^{14}}{1.75\times 10^{4}}\) hours \(=1.307212251\times 10^{10}\) hours
Step 3: Convert hours to years
Number of hours in a year \(h_{year}=8760\) hours/year
\(t_{years}=\frac{1.307212251\times 10^{10}\text{ hours}}{8760\text{ hours/year}}\)
\(t_{years}\approx1.49225\times 10^{6}\) years
Problem 3: Cost of Liquid Oxygen for Space Shuttle
Step 1: Find the total mass of liquid oxygen
The volume of liquid oxygen \(V = 143000\) gallons.
The mass per gallon \(m_{gallon}=4.322\) kg/gallon.
The total mass \(M=143000\) gallons\(\times4.322\) kg/gallon
\(M = 143000\times4.322=618046\) kg
Step 2: Calculate the total cost
The cost per kg \(C_{kg}=\$2.6\) per kg.
The total cost \(TC = M\times C_{kg}\)
\(TC=618046\) kg\(\times\$2.6\) per kg
\(TC=\$1606919.6\)
Problem 2 Answer:
\(\approx1.49\times 10^{6}\) years (rounded to 3 significant figures)
Problem 3 Answer:
\(\$1606920\) (rounded to the nearest dollar)
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Step 1: Find the total mass of liquid oxygen
The volume of liquid oxygen \(V = 143000\) gallons.
The mass per gallon \(m_{gallon}=4.322\) kg/gallon.
The total mass \(M=143000\) gallons\(\times4.322\) kg/gallon
\(M = 143000\times4.322=618046\) kg
Step 2: Calculate the total cost
The cost per kg \(C_{kg}=\$2.6\) per kg.
The total cost \(TC = M\times C_{kg}\)
\(TC=618046\) kg\(\times\$2.6\) per kg
\(TC=\$1606919.6\)
Problem 2 Answer:
\(\approx1.49\times 10^{6}\) years (rounded to 3 significant figures)
Problem 3 Answer:
\(\$1606920\) (rounded to the nearest dollar)