Question

factor the trinomial.
$a^{2}+20a + 100=square$

Explanation:

Step1: Identify the form

The trinomial $a^{2}+20a + 100$ is in the form of $x^{2}+2bx + b^{2}$, where $x = a$ and $2b=20$ (so $b = 10$).

Step2: Apply the perfect - square formula

The perfect - square formula is $x^{2}+2bx + b^{2}=(x + b)^{2}$. Substituting $x=a$ and $b = 10$ into the formula, we get $(a + 10)^{2}$.

Answer:

$(a + 10)^{2}$