Question

factoring diff / sum of cubes (i
this is the only question in this section.
question
factor ( n^3 + 1 ) completely.
answer attempt 1 out of 2

Explanation:

Step1: Identify sum of cubes

$n^3 + 1 = n^3 + 1^3$

Step2: Apply sum of cubes formula

Use $a^3+b^3=(a+b)(a^2-ab+b^2)$, where $a=n$, $b=1$
$n^3 + 1^3=(n+1)(n^2 - n\cdot1 + 1^2)$

Step3: Simplify the quadratic term

$(n+1)(n^2 - n + 1)$

Answer:

$(n+1)(n^2 - n + 1)$